Option (c) is correct

Since S is on even integer, S can be- 2, 4, 6 --- so on.

Checking the given options by taking S = 2

A.  S + 1 = 2 + 1 = 3 odd

B.  2S – 1 = 2 × 2 – 1 = 3 odd

C.  S2 – 1 = 22 – 1 = 3 odd

D.  S2 – 1 = 22 – 1 = 3 odd

E.  S2 – 2 = 22 – 2 = 2 even

Hence option (c) is correct.

विकल्प (c) सही है

चूँकि S सम पूर्णांक पर है, S हो सकता है- 2, 4, 6 --- इसी तरह।

S = 2 लेकर दिए गए विकल्पों की जाँच करें

A. S + 1 = 2 + 1 = 3 विषम

B. 2S – 1 = 2 x 2 – 1 = 3 विषम

C. S² – 1 = 2² – 1 = 3 विषम

D. S² – 1 = 2² – 1 = 3 विषम

E. S² – 2 = 2² – 2 = 2 सम

अतः विकल्प (c) सही है।

Video Explanation

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