Option (a) is correct

Let the smallest odd number be x

So the even number will be x + 11

Then the three consecutive odd numbers = x, (x + 2), (x + 4)

and three consecutive even number = (x + 11) (x + 13) (x + 15)

Now x + (x + 2) + (x + 4) + (x + 11) + (x + 13) + (x + 15) = 231

6x + 45 = 231

x = 186/6 = 31

Hence longest odd number = x + 4 = 31 + 4 = 35

largest even number = x + 15 = 31 + 15 = 46

Hence, required sum = 35 + 46 = 81

विकल्प (a) सही है

मान लीजिए कि सबसे छोटी विषम संख्या x है

तो सम संख्या x + 11 होगी

तब तीन क्रमागत विषम संख्याएँ

= x, (x + 2), (x + 4)

और तीन क्रमागत सम संख्या

= (x + 11) (x + 13) (x + 15)

अब x + (x + 2) + (x + 4) + (x + 11) + (x + 13) + (x + 15) = 231

6 x + 45 = 231

x = 186/6 = 31

अतः सबसे बड़ी विषम संख्या

= x + 4 = 31 + 4 = 35

सबसे बड़ी सम संख्या = x + 15

= 31 + 15 = 46

इसलिए, आवश्यक योग = 35 + 46

= 81