Option (b) is correct

Teachers in University A, B and C together = 11%+17%+19% = 47%

So, L = (47/100)x6400 = 3008

Teacher in Unversity D, E and F together = 6%+29%+18% = 53%

So, m = (53/100)x6400 = 3392

So, m-L = 3392-3008 = 384

Teachers in University D = (6/100) x 6400 = 384

Hence option (B) is correct

विकल्प (b) सही है

विश्वविद्यालय A, B और C के पूरे शिक्षक = 11% + 17% + 19% = 47%

इसलिए, L = 47/100 × 6400 = 3008

विश्वविद्यालय D, E और F के कुल शिक्षक = 6% + 29% + 18% = 53%

इसलिए, m = 53/(100 ) × 6400 = 3392

इसलिए, m-L = 3392 - 3008 = 384

विश्वविद्यालय D में शिक्षक = 6/100 × 6400 = 384

अतः विकल्प (b) सही है